(5x+4)(5x+4)-16y^2=0

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Solution for (5x+4)(5x+4)-16y^2=0 equation: 


Simplifying
(5x + 4)(5x + 4) + -16y2 = 0

Reorder the terms:
(4 + 5x)(5x + 4) + -16y2 = 0

Reorder the terms:
(4 + 5x)(4 + 5x) + -16y2 = 0

Multiply (4 + 5x) * (4 + 5x)
(4(4 + 5x) + 5x * (4 + 5x)) + -16y2 = 0
((4 * 4 + 5x * 4) + 5x * (4 + 5x)) + -16y2 = 0
((16 + 20x) + 5x * (4 + 5x)) + -16y2 = 0
(16 + 20x + (4 * 5x + 5x * 5x)) + -16y2 = 0
(16 + 20x + (20x + 25x2)) + -16y2 = 0

Combine like terms: 20x + 20x = 40x
(16 + 40x + 25x2) + -16y2 = 0

Solving
16 + 40x + 25x2 + -16y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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